Amelia Pond
Doctor Who

Cosplayer: Lozzie

Variant: Police/Kissagram Outfit

Status: Complete

Condition: Not Set


Holli avatar

Holli - 29th March 2012
looks awesome! you did amazing ! that didnt take you long atall !! x

Ranma1-2 avatar

Ranma1-2 - 30th March 2012
*_* sexyyyyyyy. Dont forget the fishnets!

Ranma1-2 avatar

Ranma1-2 - 30th March 2012
Did I imagine fishnets? I have fishnets on the brain atm. ^_^

Captain_Marvelous avatar

Captain_Marvelous - 30th March 2012
Aww hun you look radical! you should have said I would have lent you my police vest! :)

Lozzie avatar

Lozzie - 30th March 2012
I dont think she wears fishnets, she has the tights with the line down the back. But its just a daft thing im wearing to one of the Kita parties so im not going 100% accurate, which is why i havent bothered shelling out for a proper police vest. I wanna redo it properly for another con though :)

Thanks so much <3

Ranma1-2 avatar

Ranma1-2 - 30th March 2012
...I knew there was something non regulation about Amys outfit which said 'this is not a real police woman'. Yep black seamed tights, that would do it. ^^
It looks like a very comfy cosplay.

magsul avatar

magsul - 17th April 2012
Amazing job, you've done Amy justice! Well done! 8D
P.S - I'm sorry I missed you Kitacon Friday. ):

Lozzie avatar

Lozzie - 17th April 2012
Magsul- Thanks so very much! I was really pleased how it came out, considering i made it really last minute. I also enjoyed wearing it! Im sure our paths will cross again and we can get some photos cos your 11 is just fantastic! :)

lilkimmi27 avatar

lilkimmi27 - 17th April 2012
You really pull her off

Unknown member avatar

Anonymous - 17th April 2012
Wuff! That is all. ;P

Lozzie avatar

Lozzie - 17th April 2012
thanks so much! I really enjoyed being her :3

xJesikira avatar

xJesikira - 19th April 2012
EEEE~ It's Amy! :D
I was the doctor at the party :)

Lozzie avatar

Lozzie - 19th April 2012
Omg Jesikira!! Heyyyy!!! Is it okay for me to have you on here? I shall credit you in my photo now =D x